MATH 2060 - Burr - 16.7

1825 days ago by burr2

       
       
The part of the surface y=x^2+z^2
That lies within the cylinder x^2+y^2=4
The part of the surface y=x^2+z^2
That lies within the cylinder x^2+y^2=4
       
The hyperboloid y=x^2+z^2 and the disk x^2+z^2=1 with y=1
The hyperboloid y=x^2+z^2 and the disk x^2+z^2=1 with y=1