# MATH 2060 - Burr - 16.7

## 1825 days ago by burr2

 The part of the surface y=x^2+z^2 That lies within the cylinder x^2+y^2=4 The part of the surface y=x^2+z^2 That lies within the cylinder x^2+y^2=4
 The hyperboloid y=x^2+z^2 and the disk x^2+z^2=1 with y=1 The hyperboloid y=x^2+z^2 and the disk x^2+z^2=1 with y=1